Python에서 주어진 URL에 매개 변수 추가

Python에서 주어진 URL에 매개 변수 추가

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URL을 받았다고 가정합니다.
이미 GET 매개 변수 (예 :)가 http://example.com/search?q=question있거나 없을 수 있습니다 (예 :) http://example.com/.

이제 몇 가지 매개 변수를 추가해야합니다 {'lang':'en','tag':'python'}. 첫 번째 경우에는, 두 번째 경우에는 http://example.com/search?q=question&lang=en&tag=python— http://example.com/search?lang=en&tag=python.

이를 수행하는 표준 방법이 있습니까?

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urllib및 urlparse모듈 에는 몇 가지 단점이 있습니다. 다음은 작동하는 예입니다.

try:
    import urlparse
    from urllib import urlencode
except: # For Python 3
    import urllib.parse as urlparse
    from urllib.parse import urlencode

url = "http://stackoverflow.com/search?q=question"
params = {'lang':'en','tag':'python'}

url_parts = list(urlparse.urlparse(url))
query = dict(urlparse.parse_qsl(url_parts[4]))
query.update(params)

url_parts[4] = urlencode(query)

print(urlparse.urlunparse(url_parts))

ParseResult의 결과는 urlparse(), 읽기 전용입니다 그리고 우리는 그것을 변환해야 list우리가 데이터를 수정하려고하기 전에.

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왜

이 페이지의 모든 솔루션에 만족하지 못했기 때문에 (자 , 우리가 가장 좋아하는 복사-붙여 넣기는 어디에 있습니까? ) 여기에 답변을 기반으로 직접 작성했습니다. 그것은 완전하고 더 Pythonic하려고 노력합니다. 소비자 측 ( JS ) 친화적 인 인수 에 dict 및 bool 값에 대한 처리기를 추가 했지만 아직 선택 사항이므로 삭제할 수 있습니다.

작동 원리

테스트 1 : 새 인수 추가, 배열 및 부울 값 처리 :

url = 'http://stackoverflow.com/test'
new_params = {'answers': False, 'data': ['some','values']}

add_url_params(url, new_params) == \
    'http://stackoverflow.com/test?data=some&data=values&answers=false'

테스트 2 : 기존 인수 다시 쓰기, DICT 값 처리 :

url = 'http://stackoverflow.com/test/?question=false'
new_params = {'question': {'__X__':'__Y__'}}

add_url_params(url, new_params) == \
    'http://stackoverflow.com/test/?question=%7B%22__X__%22%3A+%22__Y__%22%7D'

대화는 저렴합니다. 코드를 보여주세요.

코드 자체. 나는 그것을 자세히 설명하려고 노력했습니다.

from json import dumps

try:
    from urllib import urlencode, unquote
    from urlparse import urlparse, parse_qsl, ParseResult
except ImportError:
    # Python 3 fallback
    from urllib.parse import (
        urlencode, unquote, urlparse, parse_qsl, ParseResult
    )


def add_url_params(url, params):
    """ Add GET params to provided URL being aware of existing.

    :param url: string of target URL
    :param params: dict containing requested params to be added
    :return: string with updated URL

    >> url = 'http://stackoverflow.com/test?answers=true'
    >> new_params = {'answers': False, 'data': ['some','values']}
    >> add_url_params(url, new_params)
    'http://stackoverflow.com/test?data=some&data=values&answers=false'
    """
    # Unquoting URL first so we don't loose existing args
    url = unquote(url)
    # Extracting url info
    parsed_url = urlparse(url)
    # Extracting URL arguments from parsed URL
    get_args = parsed_url.query
    # Converting URL arguments to dict
    parsed_get_args = dict(parse_qsl(get_args))
    # Merging URL arguments dict with new params
    parsed_get_args.update(params)

    # Bool and Dict values should be converted to json-friendly values
    # you may throw this part away if you don't like it :)
    parsed_get_args.update(
        {k: dumps(v) for k, v in parsed_get_args.items()
         if isinstance(v, (bool, dict))}
    )

    # Converting URL argument to proper query string
    encoded_get_args = urlencode(parsed_get_args, doseq=True)
    # Creating new parsed result object based on provided with new
    # URL arguments. Same thing happens inside of urlparse.
    new_url = ParseResult(
        parsed_url.scheme, parsed_url.netloc, parsed_url.path,
        parsed_url.params, encoded_get_args, parsed_url.fragment
    ).geturl()

    return new_url

몇 가지 문제가있을 수 있습니다. 문제를 찾으면 알려 주시면이 문제를 개선하겠습니다.

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You want to use URL encoding if the strings can have arbitrary data (for example, characters such as ampersands, slashes, etc. will need to be encoded).

Check out urllib.urlencode:

>>> import urllib
>>> urllib.urlencode({'lang':'en','tag':'python'})
'lang=en&tag=python'

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You can also use the furl module https://github.com/gruns/furl

>>> from furl import furl
>>> print furl('http://example.com/search?q=question').add({'lang':'en','tag':'python'}).url
http://example.com/search?q=question&lang=en&tag=python

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Yes: use urllib.

From the examples in the documentation:

>>> import urllib
>>> params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0})
>>> f = urllib.urlopen("http://www.musi-cal.com/cgi-bin/query?%s" % params)
>>> print f.geturl() # Prints the final URL with parameters.
>>> print f.read() # Prints the contents

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Based on this answer, one-liner for simple cases (Python 3 code):

from urllib.parse import urlparse, urlencode


url = "https://stackoverflow.com/search?q=question"
params = {'lang':'en','tag':'python'}

url += ('&' if urlparse(url).query else '?') + urlencode(params)

or:

url += ('&', '?')[urlparse(url).query == ''] + urlencode(params)

---

If you are using the requests lib:

import requests
...
params = {'tag': 'python'}
requests.get(url, params=params)

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Outsource it to the battle tested requests library.

This is how I will do it:

from requests.models import PreparedRequest
url = 'http://example.com/search?q=question'
params = {'lang':'en','tag':'python'}
req = PreparedRequest()
req.prepare_url(url, params)
print(req.url)

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I liked Łukasz version, but since urllib and urllparse functions are somewhat awkward to use in this case, I think it's more straightforward to do something like this:

params = urllib.urlencode(params)

if urlparse.urlparse(url)[4]:
    print url + '&' + params
else:
    print url + '?' + params

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Use the various urlparse functions to tear apart the existing URL, urllib.urlencode() on the combined dictionary, then urlparse.urlunparse() to put it all back together again.

Or just take the result of urllib.urlencode() and concatenate it to the URL appropriately.

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Yet another answer:

def addGetParameters(url, newParams):
    (scheme, netloc, path, params, query, fragment) = urlparse.urlparse(url)
    queryList = urlparse.parse_qsl(query, keep_blank_values=True)
    for key in newParams:
        queryList.append((key, newParams[key]))
    return urlparse.urlunparse((scheme, netloc, path, params, urllib.urlencode(queryList), fragment))

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I find this more elegant than the two top answers:

from urllib.parse import urlencode, urlparse, parse_qs

def merge_url_query_params(url: str, additional_params: dict) -> str:
    url_components = urlparse(url)
    original_params = parse_qs(url_components.query)
    # Before Python 3.5 you could update original_params with 
    # additional_params, but here all the variables are immutable.
    merged_params = {**original_params, **additional_params}
    updated_query = urlencode(merged_params, doseq=True)
    # _replace() is how you can create a new NamedTuple with a changed field
    return url_components._replace(query=updated_query).geturl()

assert merge_url_query_params(
    'http://example.com/search?q=question',
    {'lang':'en','tag':'python'},
) == 'http://example.com/search?q=question&lang=en&tag=python'

The most important things I dislike in the top answers (they are nevertheless good):

• Łukasz: having to remember the index at which the query is in the URL components
• Sapphire64: the very verbose way of creating the updated ParseResult

What's bad about my response is the magically looking dict merge using unpacking, but I prefer that to updating an already existing dictionary because of my prejudice against mutability.

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In python 2.5

import cgi
import urllib
import urlparse

def add_url_param(url, **params):
    n=3
    parts = list(urlparse.urlsplit(url))
    d = dict(cgi.parse_qsl(parts[n])) # use cgi.parse_qs for list values
    d.update(params)
    parts[n]=urllib.urlencode(d)
    return urlparse.urlunsplit(parts)

url = "http://stackoverflow.com/search?q=question"
add_url_param(url, lang='en') == "http://stackoverflow.com/search?q=question&lang=en"

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Here is how I implemented it.

import urllib

params = urllib.urlencode({'lang':'en','tag':'python'})
url = ''
if request.GET:
   url = request.url + '&' + params
else:
   url = request.url + '?' + params    

Worked like a charm. However, I would have liked a more cleaner way to implement this.

Another way of implementing the above is put it in a method.

import urllib

def add_url_param(request, **params):
   new_url = ''
   _params = dict(**params)
   _params = urllib.urlencode(_params)

   if _params:
      if request.GET:
         new_url = request.url + '&' + _params
      else:
         new_url = request.url + '?' + _params
   else:
      new_url = request.url

   return new_ur

참고URL : https://stackoverflow.com/questions/2506379/add-params-to-given-url-in-python